fix:推送功能registrationId没有保存,退出登录无法清理掉推送ID

This commit is contained in:
Liuyf 2025-02-13 17:21:14 +08:00
parent a12c17be7f
commit ad1ca2ec77
2 changed files with 3 additions and 3 deletions

View File

@ -77,7 +77,7 @@ platform :ios do
UI.user_error!("flavor is required") unless flavor
UI.user_error!("env is required") unless env
print_log "build #{flavor} on #{env}"
build_number = Time.now.strftime("%Y%m%d%H")
build_number = Time.now.strftime("%Y%m%d%H%M")
print_log "Build Commits #{build_number}"
build_version = $next_version # Time.now.strftime("%Y%m%d%H%M%S")
print_log "build_version #{build_version}"
@ -130,7 +130,7 @@ platform :ios do
flavor = options[:flavor]
UI.user_error!("flavor is required") unless flavor
print_log "build flavor: #{flavor}"
build_number = Time.now.strftime("%Y%m%d%H")
build_number = Time.now.strftime("%Y%m%d%H%M")
print_log "Build Commits #{build_number}"
build_version = $current_tag.match(/^v(\d+\.\d+\.\d+)/).captures[0]
print_log "build_version #{build_version}"

View File

@ -103,9 +103,9 @@ class XSJPushProvider {
//id
final String rid = await jpush.getRegistrationID();
AppLog.log('onConnected registration id : $rid');
await Storage.setString(pushDeviceID, rid);
deviceID = rid;
}
await Storage.setString(pushDeviceID, deviceID);
final MineUnbindPhoneOrEmailEntity entity = await ApiRepository.to
.pushBindAppId(deviceID, Platform.isAndroid ? 10 : 20);
if (entity.errorCode!.codeIsSuccessful) {